(3x-4)^2=4(x+3)

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Solution for (3x-4)^2=4(x+3) equation: 



(3x-4)^2=4(x+3)

We move all terms to the left:

(3x-4)^2-(4(x+3))=0



We calculate terms in parentheses: -(4(x+3)), so:

4(x+3)

We multiply parentheses

4x+12

Back to the equation:

-(4x+12)



We get rid of parentheses

(3x-4)^2-4x-12=0

We add all the numbers together, and all the variables

-4x+(3x-4)^2-12=0

We move all terms containing x to the left, all other terms to the right

-4x+(3x-4)^2=12

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